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The CSIR UGC NET December 2024 exam will be conducted on February 28, March 1 and 2 in two shifts. The first shift will be from 9 am to noon and the second shift will be from 3 pm to 6 pm
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CSIR UGC NET 2025 hall tickets now available at csirnet.nta.ac.in.
CSIR UGC NET 2025 Admit Card: The National Testing Agency (NTA) has released the admit card for the CSIR NET December 2025 exam. It can be downloaded by visiting the exam website csirnet.nta.ac.in.
The CSIR UGC NET December 2024 exam will be conducted on February 28, March 1 and 2 in two shifts. The first shift will be from 9 am to noon and the second shift will be from 3 pm to 6 pm.
How To Download CSIR NET December 2024 Admit Card?
Step 1 — To download the admit card, first go to csirnet.nta.ac.in.
Step 2 — After this, the Joint CSIR UGC NET December 2024 Admit Card link will be available on the home page.
Step 3 — Clicking on the link and a new page will open.
Step 4 — Enter your application number, date of birth, and security pin here and submit.
Step 5 — Now the admit card will open, download it and print it.
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The admit card contains crucial information including exam roll number, candidate name, exam date and time, assigned test centre address, and exam day guidelines. Candidates must review all details and in case of errors, they must report to the authorities immediately. Any issues encountered while downloading the admit card or discrepancies in the information should be reported to the NTA helpdesk at 011-40759000 or via email at csirnet@nta.ac.in.
The CSIR UGC NET determines eligibility for Junior Research Fellowship (JRF) grants and lectureships. It will be held online as a computer-based test (CBT) in English or Hindi. The three-hour exam is divided into three sections: Part A, Part B, and Part C, and consists of 200 marks. Part A focuses on General Aptitude, while Parts B and C delve into the candidate’s chosen subject. All sections consist of objective-type, multiple-choice questions. As per the markigng scheme, 25 per cent of the allotted marks is deducted for each incorrect answer.